Q. The length of major and minor axis of an ellipse are 10 and 8 respectively and its major axis along $y$-axis the equation of the ellipse referred to its centre as origin is
A) $\frac{x^{2}}{25} + \frac{y^{2}}{16} = 1$
B) $\frac{x^{2}}{16} + \frac{y^{2}}{25} = 1$
C) $\frac{x^{2}}{100} + \frac{y^{2}}{64} = 1$
D) $\frac{x^{2}}{64} + \frac{y^{2}}{100} = 1$
Explanation
(b)
Given, $2b = 10,\ 2a = 8$
$\Rightarrow \ b = 5$ and $a = 4\$
Required equation of ellipse is
$\frac{x^{2}}{16} + \frac{y^{2}}{25} = 1$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.