Q. One of the diameter of the circle $x^{2} + y^{2} - 12x + 4y + 6 = 0$ is given by
A) $x + y = 0$
B) $x + 3y = 0$
C) $x = y$
D) $3x + 2y = 0$
Explanation
(b)
The coordinates of the centre of given circle are$(6,\ - 2)$. Clearly the line $x + 3y = 0$ passes through this point. Hence, $x + 3y = 0$ is a diameter of the given circle.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.