The coaxial system of circles given by $x^{2} + y^{2} + 2gx + c = 0$ for $c

Question

The coaxial system of circles given by $x^{2} + y^{2} + 2gx + c = 0$ for $c < 0$ respects

Dr. Abubacker · Accepted Answer

(a)
The equation of a system of circle with its centre on the axis of $x$is$x^{2} + y^{2} + 2gx + c = 0$. Any point on the radical axis is $(0,\ y_{1})$
Putting$x = 0,\ y = \pm \sqrt{- c}$. If $c$ is negative we have two real points on radical axis, then the circles are said to be intersecting circles

Q. The coaxial system of circles given by $x^{2} + y^{2} + 2gx + c = 0$ for $c < 0$ respects

Explanation

Reviewed by Dr. Abubacker

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