Q. The circles $x^{2} + y^{2} - 8x + 4y + 4 = 0$ touches
A) $x$-axis
B) $y$-axis
C) Both axes
D) Neither $x$-axis not $y$-axis
Explanation
(b)
We have, $x^{2} + y^{2} - 8x + 4y + 4 = 0$
Here, centre=(4, -2)
And radius $= \sqrt{(4)^{2} + ( - 2)^{2} - 4} = 4$
Here, radius of circle is equal to $x$-coordinates of the centre
$\therefore$ Circle touches $y$-axis
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.