(a)
Since, $B$ and $C$ are the ends of diameter as $\angle BAC$ is $90{^\circ}$
$\therefore$ Equation of circle is
$x(x - 1) + y(y - 1) = 0$
$\Rightarrow x^{2} + y^{2} - x - y = 0$
Now, point $D$ satisfies this equation
$\Rightarrow 4a^{2} + 9a^{2} - 5a = 0$
$\Rightarrow a(13a - 5) = 0$
$\Rightarrow a = 0,\ a = \frac{5}{13}$