Q. The distance of the mid point of line joining two points (4, 0) and (0, 4) from the centre of the circle $x^{2} + y^{2} = 16$ is
A) $\sqrt{2}$
B) $2\sqrt{2}$
C) $3\sqrt{2}$
D) $2\sqrt{3}$
Explanation
(b)
Mid point of (4, 0) and (0, 4) is (2, 2)
Required distance$= \sqrt{(2 - 0)^{2} + (2 - 0)^{2}}$
$= \sqrt{8}$
$= 2\sqrt{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.