Q. The foci of the Basic Terms of Conics $25x^{2} + 16y^{2} - 150x = 175$ are
A) $(0, \pm 3)$
B) $(0, \pm 2)$
C) $(3, \pm 3)$
D) $(0, \pm 1)$
Explanation
(c)
Given equation can be rewritten as
$\frac{(x - 3)^{2}}{16} + \frac{y^{2}}{25} = 1$
Here, $a^{2} = 16$ and$\ b^{2} = 25$
$\therefore e = \sqrt{1 - \frac{16}{25}} = \frac{3}{5}$
Hence, the foci Basic Terms of Conics are $(0, \pm be)ie,\ (3, \pm 3)$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.