(d) Given that, $x^{2} + y^{2} + 2gx + 2fy + c = 0$ and $g^{2} + f^{2} = c$ $\therefore Radius\ of\ circle = \sqrt{g^{2} + f^{2} - c}$ $\Rightarrow Radius = 0\ \ (\because g^{2} + f^{2} = c)$ Thus given equation represents a circles of radius 0
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.