Q. The equation of tangent to the ellipse $x^{2} + \ 4y^{2} = 5$ at $( - 1,\ 1)$, is
A) $x + 4y + 5 = 0$
B) $x - 4y - 5 = 0$
C) $x + 4y - 5 = 0$
D) $x - 4y + 5 = 0$
Explanation
(d)
Equation of tangent to the ellipse
$x^{2} + 4y^{2} = 5\ at\ the\ point\ ( - 1,1)$ is
$- x + 4y = 5$
$\Rightarrow \ \ x - 4y + 5 = 0$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.