Q. The radius of any circle touching the lines $3x - 4y + 5 = 0$ and $6x - 8y - 9 = 0$ is

A) 1.9
B) 0.95
C) 2.9
D) 1.45
Explanation

(b)
Since, given lines are parallel to each other, so the line segment joining the points of contact is diameter of the circle. Distance between the lines $3x - 4y + 5 = 0$ and $3x - 4y - \frac{9}{2} = 0$ is
$\left| \frac{5 + \frac{9}{2}}{\sqrt{3^{2} + 4^{2}}} \right| = \left| \frac{19}{10} \right| = 1.9$
Length of diameter of the circle is 1.9
$\therefore Radius\ of\ circle = \frac{1.9}{2} = 0.95$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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