Q. The centre of the ellipse $9x^{2} + 25y^{2} - 18x - 100y - 166 = 0,$ is
A) $(1,1)$
B) $( - 1,2)$
C) $( - 1,1)$
D) (1,2 )
Explanation
(d)
Given equation of ellipse can be rewritten as
$(3x - 3)^{2} + (5y - 10)^{2} = 225$
$\Rightarrow \ \ \frac{9(x - 1)^{2}}{225} + \frac{25(y - 2)^{2}}{225} = 1$
$\therefore$ Centre of ellipse is$\$(1, 2)
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.