Q. Three normals to the parabola $y^{2} = x\$through point$\ (a,\ 0).$ Then,
A) $a = \frac{1}{2}$
B) $a = \frac{1}{4}$
C) $a > \frac{1}{2}$
D) $a < \frac{1}{2}$
Explanation
(c)
We know that, if three normals to the parabola $y^{2} = 4ax\$through point$\ (h,\ k),\$then$\ h > 2a$
Here, $h = a$ and $a = \frac{1}{4}$
$\therefore\ a > 2.\frac{1}{4}\ \ \Rightarrow \ a > \frac{1}{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.