Q. If tangent at any point $P$ on the ellipse ${7x}^{2} + {26y}^{2} = 12$ cuts the tangent at the end points of the major axis at the points $A$ and $B$, then the circle with $AB$ as diameter passes through a fixed point whose coordinates are

A) $\left( \pm \sqrt{a^{2} - b^{2}},\ 0 \right)$
B) $\left( \pm \sqrt{a^{2} + b^{2}},\ 0 \right)$
C) $\left( 0,\ \pm \sqrt{a^{2} - b^{2}} \right)$
D) $\left( 0,\ \pm \sqrt{a^{2} + b^{2}} \right)$
Explanation

The correct answer is Option A: $\left( \pm \sqrt{a^{2} - b^{2}},\ 0 \right)$.

A detailed explanation for this question is being prepared.

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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