Q. The slope of the tangent at the point $(h,\ h)$ to the circle $x^{2} + y^{2} = a^{2}$ is
A) 0
B) 1
C) $- 1$
D) Will depend on $h$
Explanation
(c)
Given circle is $x^{2} + y^{2} = a^{2}\$ and point is $(h,\ h)$
$\therefore$ Equation of tangent at $(h,\ h)$ is
$xh + yh = a^{2}\ \ \Rightarrow \ \ \ y = - x + \frac{a^{2}}{h}$
$\therefore$ Slope of the tangent is $- 1$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.