Q. If $x^{2} + 6x + 20y - 51 = 0$, then axis of parabola is
A) $x + 3 = 0$
B) $x - 3 = 0$
C) $x = 1$
D) $x + 1 = 0$
Explanation
(a)
Given, $(x + 3)^{2} = - 20(y - 3)$
This is of the form $X^{2} = - 4\ aY$
$\therefore$ Axis of such parabola is given by$\$
$X = 0$
$\Rightarrow \ (x + 3) = 0$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.