(b)
If the line $y = mx + c$ touches the parbola $y^{2} = 4ax$, then
$y = mx + \frac{a}{m}$
$\Rightarrow \ \ \ my = m^{2}\ x + a\$
$\Rightarrow \ my = x + am^{2}\ \ \left\lbrack replacing\ m\ by\ \frac{1}{m} \right\rbrack$
$\Rightarrow \ x - my + am^{2} = 0$