(a)
Given equation of parabola can be rewritten as
${(y - 1)}^{2} = 4(x - 1)$
Axis of parabola is $y = 1$, equation of normal is
$(y - 1) = m(x - 1) - 2m - m^{3}$
Let $(h,\ 1)$ is a point on it’s axis, then
$0 = m(h - 1) - 2m - m^{3}$
$\Rightarrow m^{2} = h - 3$
$\Rightarrow h \geq 3$ for real values of $m$