Q. If one of the diameters of the circle $x^{2} + y^{2} - 2x - 6y + 6 = 0$ is a chord to the circle with centre (2, 1), then the radius of the circle is
A) $\sqrt{3}$
B) $\sqrt{2}$
C) 3
D) 2
Explanation
(c)
The centre of given circle is (1, 3) and radius is 2. So, $AB$ is a diameter of the given circle has its mid point as (1, 3). The radius of the required circle is 3
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Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.