Q. The equation of the directrix of $(x - 1)^{2}\ = 2(y - 2)$ is
A) $2y + 3 = 0$
B) $2x + 1 = 0$
C) $2x - 1 = 0$
D) $2y - 3 = 0$
Explanation
(d)
Equation of directrix of $(x - 1)^{2} = 2(y - 2)$ is
$y - 2 = - \frac{1}{2}$
$\Rightarrow \ 2y - 3 = 0$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.