Q. The equations of the asymptotes of the hyperbola $2x^{2} + 5xy + 2y^{2} - 11x - 7y - 4 = 0$ are

A) $2x^{2} + 5xy + 2y^{2} - 11x - 7y - 5 = 0$
B) $2x^{2} + 4xy + 2y^{2} - 7x - 11y + 5 = 0$
C) $2x^{2} + 5xy + 2y^{2} - 11x - 7y + 5 = 0$
D) None of the above
Explanation

(c)
The pair of asymptotes and second degree curve differ by a constant.
$\therefore\$Pair of asymptotes is
$2x^{2} + 5xy + 2y^{2} - 11x - 7y + \lambda = 0$ …(i)
Hence, Eq. (i) represents a pair of straight lines.
$\therefore\ \mathrm{\Delta} = 0$
$\Rightarrow \ \ 2 \times 2 \times \lambda + 2 \times - \frac{7}{2} \times - \frac{11}{2} \times \frac{5}{2} - 2 \times \left( - \frac{7}{2} \right)^{2} - 2 \times \left( - \frac{11}{2} \right)^{2} - \lambda \times \left( \frac{5}{2} \right)^{2} = 0$
$\Rightarrow \ \ \lambda = 5$
From Eq.(i), pair of asymptotes is
$2x^{2} + 5xy + 2y^{2} - 11x - 7y + 5 = 0\$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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