Q. A circle passes through $(0,\ 0),(a,\ 0)\ and\ (0,\ b)$ the coordinates of its centre are
A) $\left( \frac{b}{2},\ \frac{a}{2} \right)$
B) $\left( \frac{a}{2},\ \frac{b}{2} \right)$
C) $(b,\ a)$
D) $(a,\ b)$
Explanation
(b)
Circle through the points $(0,\ 0),\ (a,\ 0)$ and $(0,\ b)$ is
$x^{2} + y^{2} - ax - by = 0$
Its centre is $\left( \frac{a}{2},\frac{b}{2} \right)$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.