Q. Equation of tangents to the ellipse $\frac{x^{2}}{9} + \frac{y^{2}}{4} = 1$, which are perpendicular to the line $3x + 4y = 7$, are

A) $4x - 3y = \pm 6\sqrt{5}$
B) $4x - 3y = \pm \sqrt{12}$
C) $4x - 3y = \pm \sqrt{2}$
D) $4x - 3y = \pm 1$
Explanation

(a)
Let the equation of tangent which is perpendicular to the line $3x + 4y = 7,\ is\ 4x - 3y = \lambda \Rightarrow \ y = \frac{4}{3}x - \frac{\lambda}{3}$
Since, it is a tangent to the ellipse
$\therefore\left( \frac{\lambda}{3} \right)^{2} = 9 \times \left( \frac{4}{3} \right)^{2} + 4\ \ \ \lbrack\therefore a^{2} = 9,\ b^{2} = 4\rbrack$
$\Rightarrow \ \ \lambda^{2} = 180\ \Rightarrow \ \lambda = \pm 6\sqrt{5}$
$\therefore$ Equation is$\ 4x - 3y = \pm 6\sqrt{5}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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