Q. The equation of the tangent to the circle $x^{2} + y^{2} = 4$, which are parallel to $x + 2y + 3 = 0$, are

A) $x - 2y = 2$
B) $x + 2y = \pm 2\sqrt{3}$
C) $x + 2y = \pm 2\sqrt{5}$
D) $x - 2y = \pm 2\sqrt{5}$
Explanation

(c)
Let the equation of tangent parallel to $x + 2y + 3 = 0$ be $x + 2y + \lambda = 0$
Condition for tangency
$\left( - \frac{\lambda}{2} \right)^{2} = 4\left( 1 + \frac{1}{4} \right)\ \ \ \ \ \lbrack\because\ \ c^{2} = a^{2}(1 + m^{2})\rbrack$
$\Rightarrow \ \ \ \lambda^{2} = 20\ \ \ \Rightarrow \ \ \ \ \lambda = \pm 2\sqrt{5}$
$\therefore$Required equation of tangent is
$x + 2y = \pm 2\sqrt{5}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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