(b)
The intersection points of given curves are (1, 0) and $\left( - \frac{13}{5},\ - \frac{6}{5} \right)$
$\therefore$ The distance between these two points
$= \sqrt{\left( 1 + \frac{13}{5} \right)^{2} + \left( 0 + \frac{6}{5} \right)^{2}}$
$= \frac{1}{5}\sqrt{324 + 36}$
$= \frac{6}{5}\sqrt{10}$