Q. The radius of the circle passing through the point (6, 2) and two of whose diameters are $x + y = 6$ and $x + 2y = 4$, is
A) 4
B) 6
C) 20
D) $\sqrt{20}$
Explanation
(d)
Centre is the point of intersection of two diameter, $ie$, the point of intersection of two diameters is $C(8,\ - 2)$, therefore the distance from the centre to the point $P(6,\ 2)$ is
$r = CP = \sqrt{4 + 16} = \sqrt{20}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.