Q. If the lines joining the foci of the ellipse $\frac{x^{2}}{a^{2}\ \ } + \frac{y^{2}}{b^{2}}\ = \ 1$, where $a > b\$ and an extremity of its minor axis are inclined at an angle $60{^\circ}$, then the eccentricity of the ellipse is

A) $- \frac{\sqrt{3}}{2}$
B) $\frac{1}{2}$
C) $\frac{\sqrt{5}}{2}$
D) $\frac{\sqrt{7}}{3}$
Explanation

(b)
In $\mathrm{\Delta}CBF;\tan{30{^\circ} = \frac{F^{''}C}{b}} \Rightarrow F^{''}C = \frac{b}{\sqrt{3}}$
[image:11_image51.emf]
$\Rightarrow \ ae = \frac{b}{\sqrt{3}}\ \Rightarrow \ a^{2}e^{2} = \frac{1}{3}\left\lbrack a^{2}\left( 1 - e^{2} \right) \right\rbrack$
$\Rightarrow \ 4e^{2} = 1\ \Rightarrow \ e = \frac{1}{2}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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