Q. The equation of a tangent parallel to $y = x$ drawn to $\frac{x^{2}}{3} - \frac{y^{2}}{2} = 1$, is
A) $x - y + 1 = 0$
B) $x - y + 2 = 0$
C) $x + y - 1 = 0$
D) $x - y + 2 = 0$
Explanation
(a)
Let $y = x + c$ is parallel to the given line. Since, it is a tangent to the given hyperbola
$c^{2} = 3 - 2\ \ \Rightarrow \ c = \pm 1$
So, required tangents are $y = x \pm 1$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.