Q. A hyperbola has the asymptotes $x + 2y = 3$ and $x - y = 0$ and passes through (2, 1). Its centre is
A) (1, 2)
B) (2, 2)
C) (1, 1)
D) (2, 1)
Explanation
(c)
Equation of asymptotes are
$x + 2y = 3$ …(i)
and $x - y = 0$
On solving Eqs.(i) and (ii), we get
$x = 1,\ y = 1$
$\therefore$ Centre of hyperbola is $(1,1)$ because asymptotes passes through the centre of the hyperbola.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.