Let a focal chord of parabola $y^{2} = 16x$ cuts it at points $(f,\ g)$ and $(h,\ k)$ Then, $f.h$ is equal to

Question

Dr. Abubacker · Accepted Answer

(b)
Let $(f,g)$and$\ (h,k)$are $(4t_{1}^{2},8t_{1})$ and $(4t_{2}^{2},8t_{2})$
respectively. Since, they are end points of a focal chord.
$	herefore t_{1}t_{2} = - 1$
Now, $fh = 4t_{1}^{2}.4t_{2}^{2} = 16\left( t_{1}t_{2} ight)^{2} = 16$

Q. Let a focal chord of parabola $y^{2} = 16x$ cuts it at points $(f,\ g)$ and $(h,\ k)$ Then, $f.h$ is equal to

Explanation

Reviewed by Dr. Abubacker

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