Explanation

The water potential ($\Psi_{\omega}$) is equal to osmotic potential $(\Psi_{S}) +$ pressure potential ($\Psi_{P}$). Osmotic potential is always in negative value. The water potential is the chemical potential of water, which is equivalant to DPD with negative sign. Therefore, water potential ($\Psi$) of cell A is $\Psi_{A} = \Psi_{S} + \Psi_{P} = - 18 + 8 = - 10$ Water potential of cell B ($\Psi_{B}$) is $\Psi_{B} = \Psi_{S} + \Psi_{P} = - 14 + 2 = - 12$ Since, water moves from higher water potential to lower potential, i.e., the flow of water will be from cell A($- 10$ bars) to cell B ($- 12$ bars)