(c)
Let the extremities of focal chords be $A(at_{1}^{2},2at_{1})$ and $B\left( at_{2}^{2},2at_{2} \right)$
The equation of tangents at $A$ and $B$ are
$t_{1y} = x + at_{2}^{2}$ and $t_{2}y = x + at_{2}^{2}$
which meets the points $C$
Slopes of these lines are $m_{1} = \frac{1}{t_{1}\ },m_{2} = \frac{1}{t_{2}}$
Now, $m_{1}m_{2} = \frac{1}{t_{1}} \times \frac{1}{t_{2}}$
$= \frac{1}{- 1}\ \ (\because t_{1}t_{2} = - 1)$
Hence, $\angle ACB = 90{^\circ} = \frac{\pi}{2}$