(b) Given, $y = a\tan\alpha + a$ Condition for tangency is $a^{2} = a^{2}(1 + \tan^{2}\alpha)$ $\lbrack\because\ \ c^{2} = a^{2}(1 + m^{2})\rbrack$ $\Rightarrow \ \ \sec^{2}\alpha = 1$ $\Rightarrow \ \ \cos^{2}\alpha = 1$
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Ph.D. in Physics with 19+ years of teaching experience.