Q. The eccentricity of the hyperbola $5x^{2} - 4y^{2} + 20x + 8y = 4$ is
A) $\sqrt{2}$
B) $\frac{3}{2}$
C) 2
D) 3
Explanation
(b)
Given hyperbola can be rewritten as
$\frac{(x + 2)^{2}}{4} - \frac{(y - 1)^{2}}{5} = 1$
$\therefore\ e = \ \sqrt{\frac{4 + 5}{4}\ } = \sqrt{\frac{9}{4}} = \frac{3}{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.