Q. The area of the triangle formed by the tangent at (3, 4) to the circle $x^{2} + y^{2} = 25$ and the coordinate axes is

A) $\frac{24}{25}$
B) 0
C) $\frac{325}{24}$
D) $- \left( \frac{24}{25} \right)$
Explanation

(c)
The equation of the tangent at $P(3,\ 4)$ to the circle $x^{2} + y^{2} = 25$is$3x + 4y = 25$, which meets the coordinate axes at $A\left( \frac{25}{3},0 \right)$ and$B\left( 0,\frac{25}{4} \right)$. If $O$ be the origin, then the $\mathrm{\Delta}OAB$ is a right angled triangle with $OA = \frac{25}{3}$ and $OB = \frac{25}{4}$
Area of the $\mathrm{\Delta}OAB = \frac{1}{2} \times OA \times OB = \frac{1}{2} \times \frac{25}{3} \times \frac{25}{4} = \frac{625}{24}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

Want more practice?
Practice Conic Sections MCQs