Q. If $(a\cos\alpha,\ b\sin{\alpha)}$, $(a\cos\beta,\ b\ \sin{\beta)}$ are the end points of a focal chord of an ellipse $b^{2}x^{2} + a^{2}y^{2} = a^{2}b^{2}$, then which of the following is correct?

A) $e = \frac{\sin{\alpha - \sin\beta}}{\sin{(\alpha - \beta)}}$
B) $e = \frac{\cos\left( \frac{\alpha - \beta}{2} \right)}{\cos\left( \frac{\alpha + \beta}{2} \right)}$
C) $\frac{e - 1}{e + 1} = \tan\frac{\alpha}{2}\tan\frac{\beta}{2}$
D) None of these
Explanation

(b)
If $(a\cos\alpha,\ b\sin{\alpha)}$and $(a\cos\beta,\ b\sin{\beta)}$ are the end points of chord, then equation of chord is
$\frac{x}{a}\cos{\left( \frac{\alpha + \beta}{2} \right) + \frac{y}{b}\sin{\left( \frac{\alpha + \beta}{2} \right) = \cos\left( \frac{\alpha - \beta}{2} \right)}}$
If it is a focal chord, it passes through $(ae,\ 0)$, so
$e\cos\left( \frac{\alpha + \beta}{2} \right) = \cos\left( \frac{\alpha - \beta}{2} \right)$
$\Rightarrow e = \frac{\cos\left( \frac{\alpha - \beta}{2} \right)}{\cos\left( \frac{\alpha + \beta}{2} \right)}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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