The point $P(9/2,6)$ lies on the parabola $y^{2} = 4ax$, then parameter of the point $P$ is

Question

Dr. Abubacker · Accepted Answer

(d)
Any point on the parabola $y^{2} = 4\ ax$ is $\left( at^{2},\ 2at ight)$
$	herefore\ at^{2} = \frac{9}{2}$
and $2at = 6\  \Rightarrow \ t = \frac{3}{a}$ …(i)
$	herefore\ a\left( \frac{3}{a} ight)^{2} = \frac{9}{2}\  \Rightarrow \ a = 2$
On putting the value of $a$ in Eq. (i), we get
$t = \frac{3}{2}$
$	herefore$ Parameter of the point $P$ is $\frac{3}{2}$

Q. The point $P(9/2,6)$ lies on the parabola $y^{2} = 4ax$, then parameter of the point $P$ is

Explanation

Reviewed by Dr. Abubacker

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