If $P$ is any point on the ellipse $\frac{x^{2}}{36} + \frac{y^{2}}{16} = 1\$and $S$ and $S'$ are the foci, then $PS + PS'$ is equal to

Question

Dr. Abubacker · Accepted Answer

(d)
Here, $a^{2} = 36,\ b^{2} = 16\$
Since,$a >$b, so the sum of the focal distance of any point $P\$on the ellipse is $PS + PS^{'} = 2a$
$\Rightarrow \ \ PS + PS^{'} = 2 	imes 6 = 12$

Q. If $P$ is any point on the ellipse $\frac{x^{2}}{36} + \frac{y^{2}}{16} = 1\$and $S$ and $S'$ are the foci, then $PS + PS'$ is equal to

Explanation

Reviewed by Dr. Abubacker

Want more practice?