Q. The equation of the ellipse having vertices at $( \pm$5,0) and $( \pm 4,0)$ is

A) $\frac{x^{2}}{25} + \ \frac{y^{2}}{16} = 1$
B) $9x^{2}\ + 25y^{2} = 225$
C) $\frac{x^{2}}{9} + \ \frac{y^{2}}{25} = 1$
D) $4x^{2}\ + 5y^{2} = 20$
Explanation

(b)
The vertices and foci of an ellipse are $( \pm 5,\ 0)$ and $( \pm 4,\ 0)$ respectively
$\therefore a = 5$ and $ae = 4$
$\Rightarrow \ \ e = \frac{4}{5}$
$\because\ e = \sqrt{1 - \frac{b^{2}}{a^{2}}}$
$\Rightarrow \ \ \frac{16}{25} = 1 - \frac{b^{2}}{25}$
$\Rightarrow \ \ b^{2} = 9\$
Hence, equation of an ellipse is
$\frac{x^{2}}{25} + \frac{y^{2}}{9} = 1\ \Rightarrow \ 9x^{2} + 25y^{2} = 225$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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