Q. If the chord of contact of tangents from a point on the circle $x^{2} + y^{2} = r_{1}^{2}$ to the circle $x^{2} + y^{2} = r_{2}^{2}$ touches the circle $x^{2} + y^{2} = r_{3}^{2}$, then $r_{,},\ r_{2},r_{3}$ are in

A) AP
B) HP
C) GP
D) AGP
Explanation

(c)
Chord of contact of tangents at any point $P\left( x_{1},y_{1} \right)$ on the circle $x^{2} + y^{2} = r_{1}^{2}$ to the circle $x^{2} + y^{2} = r_{2}^{2}$ is $xx_{1} + yy_{1} = r_{2}^{2}$ which touches the circle $x^{2} + y^{2} = r_{3}^{2}$
$\therefore\ \ \ \frac{|0.x_{1} + 0.y_{1} - r_{2}^{2}|}{\sqrt{x_{1}^{2} + y_{1}^{2}}} = r_{3}$
$\Rightarrow \ \ \ r_{2}^{2} = r_{3}.\sqrt{x_{1}^{2} + y_{1}^{2}} = r_{3}.r_{1}\ \ \lbrack\because r_{1}^{2} = x_{1}^{2} + y_{1}^{2}\rbrack$
So, $r_{1},r_{2},\ r_{3}$ are in GP

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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