A point $P$ moves in such a way that the ratio of its distance from two coplanar points is always a fixed number$(
eq 1)$. Then, its locus is a

Question

A point $P$ moves in such a way that the ratio of its distance from two coplanar points is always a fixed number$( 
eq 1)$. Then, its locus is a

Dr. Abubacker · Accepted Answer

(b)
Let two coplanar points be (0, 0) and $(a,\ 0)$
$	herefore\ \ \ \frac{\sqrt{x^{2} + y^{2}}}{\sqrt{(x - a)^{2} + y^{2}}} = \lambda\ \ \ \ \ \lbrack\lambda 
eq 1brack$
[where $\lambda$ is any number]
$\Rightarrow \ \ x^{2} + y^{2} + \left( \frac{\lambda^{2}}{\lambda^{2} - 1} ight)\left( a^{2} - 2ax ight) = 0$
Which is the equation of circle

Q. A point $P$ moves in such a way that the ratio of its distance from two coplanar points is always a fixed number$( \neq 1)$. Then, its locus is a

Explanation

Reviewed by Dr. Abubacker

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