(d)
Equation of tangent to $y^{2} = 4x\$is $y = mx + \frac{1}{m}$
Since, tangent passes through $( - 1,\ - 6)$
$\therefore - 6 = - m + \frac{1}{m}\ \Rightarrow \ m^{2} - 6m - 1 = 0$
Here, $m_{1}m_{2} = - 1$
$\therefore$ Angle between them is$\ 90{^\circ}$