(c)
Given curve is $y^{2} = 4x$ …(i)
Let the equation of line be $y = mx + c$
Since, $\frac{dy}{dx} = m = 1$ and above line is passing through the point (0, 1)
$1 = 1(0) + c\ \Rightarrow \ c = 1$
$y = x + 1$ …(ii)
On solving Eqs. (i) and (ii), we get
$x = 1$ and $y = 2$
This shows that line touch the curve at one point. So, length of intercept is zero.