(d)
Equation of auxiliary circle is
$x^{2} + y^{2} = 9\ \ \ldots(i)$
[image:11_image79.emf]
Equation of $AM$ is $\frac{x}{3} + \frac{y}{1} = 1\ \ \ldots\ (ii)$
On solving Eqs. (i) and (ii) , we get $M\left( - \frac{12}{5},\frac{9}{5} \right)$
Now, area of $\mathrm{\Delta}AOM = \frac{1}{2}.OA \times MN$
$= \frac{27}{10}\ sq\ unit\$