Q. The line passing through the extremity $A$ of the major axis and extremity $B$ of the minor axis of the ellipse $x^{2} + 9y^{2} = 9$ meets its auxiliary circle at the point $M$. Then, the area of the triangle with vertices at $A,\ M$ and the origin $O$ is

A) $\frac{31}{10}$
B) $\frac{29}{10}$
C) $\frac{21}{10}$
D) $\frac{27}{10}$
Explanation

(d)
Equation of auxiliary circle is
$x^{2} + y^{2} = 9\ \ \ldots(i)$
[image:11_image79.emf]
Equation of $AM$ is $\frac{x}{3} + \frac{y}{1} = 1\ \ \ldots\ (ii)$
On solving Eqs. (i) and (ii) , we get $M\left( - \frac{12}{5},\frac{9}{5} \right)$
Now, area of $\mathrm{\Delta}AOM = \frac{1}{2}.OA \times MN$
$= \frac{27}{10}\ sq\ unit\$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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