Q. The radius of the circle $x^{2} + y^{2} + 4x + 6y + 13 = 0$ is
A) $\sqrt{26}$
B) $\sqrt{13}$
C) $\sqrt{23}$
D) 0
Explanation
(d)
Given equation of circle can be rewritten as
$(x + 2)^{2} + (y + 3)^{2} = 0$
$\therefore$ Radius of circle is 0
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.