Q. Vertex of the parabola $9x^{2} - 6x + 36y + 9 = 0$ is
A) $(1/3,\ - 2/9)$
B) $( - 1/3,\ - 1/2)$
C) $( - 1/3,\ 1/2)$
D) (1/3, 1/2)
Explanation
(a)
Given, $(3x - 1)^{2} = - 4\ (9y + 2)$
Hence, the vertex is $\left( \frac{1}{3}\ ,\frac{- 2}{9}\ \right)$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.