Explanation

(b)
Given, $\frac{x^{2}}{5} + \frac{y^{2}}{9} = 1$
Here, $a^{2} = 5,\ {\ \ \ \ b}^{2} = 9$
Equation of normal to the ellipse at the point (0, 3) is
$\frac{x - 0}{0/5} = \frac{y - 3}{3/9}\ \ \left\lbrack \therefore\frac{x - x_{1}}{x_{1}/a^{2}} = \frac{y - y_{1}}{y_{1}/b^{2}} \right\rbrack$
$\Rightarrow \ \ \ \ x = 0\$
Which is the equation of$\ y -$axis