Q. Equation of chord of the parabola $y^{2} = 16x$ whose mid point is (1, 1), is
A) $x + y = 2$
B) $x - y = 0$
C) $8x + y = 9$
D) $8x - y = 7$
Explanation
(d)
Given equation of parabola is $y^{2} = 16x$
If $(1,\ 1)$ is the mid point of the chord, then its equation of chord is
$T = S_{1}$
$\therefore y(1) - 8(x + 1) = 1 - 16$
$\Rightarrow y - 8x - 8 = - 15$
$\Rightarrow 8x - y = 7$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.