(d) Since, distance between directrices, $\frac{2a}{e} = 10$ $\Rightarrow \ a = \frac{10 \times \sqrt{2}}{2} = 5\sqrt{2}$ $\therefore$Distance between foci, $2ae = 2 \times 5\sqrt{2} \times \sqrt{2}$ $= \ 20$
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Ph.D. in Physics with 19+ years of teaching experience.