Q. The eccentricity of the hyperbola $9x^{2} - 16y^{2} - 18x - 64y - 199 = 0$ is
A) $\frac{16}{9}$
B) $\frac{5}{4}$
C) $\frac{25}{16}$
D) Zero
Explanation
(b)
Given equation can be rewritten as
$\frac{(x - 1)^{2}}{16} - \frac{(y + 2)^{2}}{9} = 1$
$\therefore\ e = \sqrt{\frac{16 + 9}{16}} = \frac{5}{4}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.