Q. The point $(4, - 3)$ with respect to the ellipse $4x^{2} + 5y^{2} = 1$ is
A) Lies on the curve
B) Is inside the curve
C) Is outside the curve
D) Is focus of the curve
Explanation
(c)
Let $S \equiv 4x^{2} + 5y^{2} - 1 = 0$
At $(4, - 3)$,
$S_{1} = 4(4)^{2} + 5( - 3)^{2} - 1 = 108 > 0$
Hence, point lies outside the curve
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.